The 1812 United States presidential election in Kentucky took place between 30 October and 2 December 1812, as part of the 1812 United States presidential election. Voters chose twelve representatives, or electors to the Electoral College, who voted for President and Vice President. Kentucky had gained four electors compared to the previous election in 1808.
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Kentucky cast twelve electoral votes for the Democratic-Republican candidate and incumbent President James Madison over the Federalist candidate DeWitt Clinton. The electoral votes for Vice president were cast for Madison's running mate Elbridge Gerry from Massachusetts. The state was divided into three electoral districts with four electors each, whereupon each district's voters chose the electors.[1]
Results
edit| 1812 United States presidential election in Kentucky[2] | |||||
|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | |
| Democratic-Republican | James Madison (incumbent) | 8,501 | 95.2% | 12 | |
| Federalist | DeWitt Clinton | 433 | 4.8% | 0 | |
| Totals | 8,934 | 100.0% | 12 | ||
See also
editReferences
edit- ^ "1812 Presidential General Election Results". U.S. Election Atlas. Retrieved July 14, 2023.
- ^ "1812 Presidential Election". 270towin.com. Retrieved July 14, 2023.