1812 United States presidential election in Kentucky

The 1812 United States presidential election in Kentucky took place between 30 October and 2 December 1812, as part of the 1812 United States presidential election. Voters chose twelve representatives, or electors to the Electoral College, who voted for President and Vice President. Kentucky had gained four electors compared to the previous election in 1808.

1812 United States presidential election in Kentucky
← 1808 30 October - 2 December 1812 1816 →
 
Nominee James Madison DeWitt Clinton
Party Democratic-Republican Federalist
Home state Virginia New York
Running mate Elbridge Gerry Jared Ingersoll
Electoral vote 12 0
Popular vote 8,501 433
Percentage 95.2% 4.8%

Kentucky cast twelve electoral votes for the Democratic-Republican candidate and incumbent President James Madison over the Federalist candidate DeWitt Clinton. The electoral votes for Vice president were cast for Madison's running mate Elbridge Gerry from Massachusetts. The state was divided into three electoral districts with four electors each, whereupon each district's voters chose the electors.[1]

Results

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1812 United States presidential election in Kentucky[2]
Party Candidate Votes Percentage Electoral votes
Democratic-Republican James Madison (incumbent) 8,501 95.2% 12
Federalist DeWitt Clinton 433 4.8% 0
Totals 8,934 100.0% 12

See also

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References

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  1. ^ "1812 Presidential General Election Results". U.S. Election Atlas. Retrieved July 14, 2023.
  2. ^ "1812 Presidential Election". 270towin.com. Retrieved July 14, 2023.