1824 Maryland gubernatorial election

The 1824 Maryland gubernatorial election was held on 13 December 1824 in order to elect the governor of Maryland. Incumbent Democratic-Republican governor Samuel Stevens Jr. was re-elected by the Maryland General Assembly against former Federalist governor Charles Goldsborough, Democratic-Republican candidate Roger B. Taney and Federalist candidates Robert Henry Goldsborough and John Eager Howard.[1]

1824 Maryland gubernatorial election

← 1823 13 December 1824 1826 →
 
Nominee Samuel Stevens Jr.
Party Democratic-Republican
Popular vote 67
Percentage 85.90%

Governor before election

Samuel Stevens Jr.
Democratic-Republican

Elected Governor

Samuel Stevens Jr.
Democratic-Republican

General election

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On election day, 13 December 1824, incumbent Democratic-Republican governor Samuel Stevens Jr. was re-elected by the Maryland General Assembly, thereby retaining Democratic-Republican control over the office of governor. Stevens was sworn in for his third term on 3 January 1825.[2]

Results

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Maryland gubernatorial election, 1824
Party Candidate Votes %
Democratic-Republican Samuel Stevens Jr. (incumbent) 67 85.90
Did Not Vote 5 6.41
Federalist Charles Goldsborough 3 3.85
Democratic-Republican Roger B. Taney 1 1.28
Federalist Robert Henry Goldsborough 1 1.28
Federalist John Eager Howard 1 1.28
Total votes 78 100.00
Democratic-Republican hold

References

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  1. ^ "Samuel Stevens Jr". National Governors Association. Retrieved 27 April 2024.
  2. ^ "MD Governor". ourcampaigns.com. 26 August 2004. Retrieved 27 April 2024.