The 1828 United States presidential election in Maine took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose nine representatives, or electors to the Electoral College, who voted for the president and vice president.
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 County Results
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Maine voted for the National Republican candidate, John Quincy Adams, over the Democratic candidate, Andrew Jackson. Adams won Maine by a margin of 19.68%. Adams received eight electoral votes and Jackson received one.
With 59.71% of the popular vote, Maine would prove to be Adams' fifth strongest state in the 1828 election after Rhode Island, Massachusetts, Vermont and Connecticut.[1]
This was the only time prior to the 2016 election (when Republican nominee Donald Trump received one of the state's four votes) that an electoral vote split occurred in Maine.
Results
edit| 1828 United States presidential election in Maine[2] | |||||
|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | |
| National Republican | John Quincy Adams (incumbent) | 20,773 | 59.71% | 8 | |
| Democratic | Andrew Jackson | 13,927 | 40.03% | 1 | |
| N/A | Other | 89 | 0.26% | 0 | |
| Totals | 34,789 | 100.0% | 9 | ||
See also
editReferences
edit- ^ "1828 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.
- ^ "1828 Presidential General Election Results - Maine". U.S. Election Atlas. Retrieved February 28, 2013.