1836 New Hampshire gubernatorial election

The 1836 New Hampshire gubernatorial election was held on 8 March 1836 in order to elect the Governor of New Hampshire. Former Democratic United States Senator from New Hampshire Isaac Hill defeated Whig nominee Joseph Healey and former Federalist Attorney General of New Hampshire George Sullivan.[1]

1836 New Hampshire gubernatorial election

← 1835 8 March 1836 1837 →
 
Nominee Isaac Hill Joseph Healey George Sullivan
Party Democratic Whig
Popular vote 24,904 2,566 2,230
Percentage 81.22% 8.37% 7.27%

County results
Hill:      50–60%      60–70%      80–90%      90-100%

Governor before election

William Badger
Democratic

Elected Governor

Isaac Hill
Democratic

General election

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On election day, 8 March 1836, Democratic nominee Isaac Hill won the election by a margin of 22,338 votes against his foremost opponent Whig nominee Joseph Healey, thereby retaining Democratic control over the office of Governor. Hill was sworn in as the 16th Governor of New Hampshire on 2 June 1836.[2]

Results

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New Hampshire gubernatorial election, 1836
Party Candidate Votes %
Democratic Isaac Hill 24,904 81.22
Whig Joseph Healey 2,566 8.37
George Sullivan 2,230 7.27
Scattering 961 3.14
Total votes 30,661 100.00
Democratic hold

References

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  1. ^ "Isaac Hill". National Governors Association. Retrieved 2 April 2024.
  2. ^ "NH Governor". ourcampaigns.com. 3 June 2005. Retrieved 2 April 2024.