The 1836 United States presidential election in Massachusetts took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose 14 representatives, or electors to the Electoral College, who voted for President and Vice President.
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| Turnout | 43.4%[1]  4.0 pp | |||||||||||||||||||||||||
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 County results
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Massachusetts voted for Whig candidate and state native Daniel Webster over the Democratic candidate, Martin Van Buren. Webster won Massachusetts by a margin of 10.32%.
In a unique strategy to throw the election into the house of representatives, the Whigs ran four different candidates in different sections of the United States. This is the only state in which Daniel Webster was on the ballot.[2]
Results
edit| 1836 United States presidential election in Massachusetts[3] | |||||
|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | |
| Whig | Daniel Webster | 41,201 | 55.13% | 14 | |
| Democratic | Martin Van Buren | 33,486 | 44.81% | 0 | |
| N/A | Other | 45 | 0.06% | 0 | |
| Totals | 74,732 | 100.00% | 14 | ||
See also
editReferences
edit- ^ Bicentennial Edition: Historical Statistics of the United States, Colonial Times to 1970, part 2, p. 1072.
- ^ "Presidential Election of 1836 - 270toWin". 270toWin.com. Retrieved August 4, 2022.
- ^ "1836 Presidential General Election Results - Massachusetts". U.S. Election Atlas. Retrieved August 4, 2012.
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