The 1836 United States presidential election in New Hampshire took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for President and Vice President.
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 County Results
Van Buren 50-60% 60-70% 70-80% 80-90%
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New Hampshire voted for the Democratic candidate, Martin Van Buren, over Whig candidate William Henry Harrison. Van Buren won New Hampshire by a margin of 50.02%. As of 2020, this remains the strongest ever performance by any presidential candidate in New Hampshire since the creation of the modern Democratic party in 1828.
Results
edit| 1836 United States presidential election in New Hampshire[1] | ||||||||
|---|---|---|---|---|---|---|---|---|
| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Democratic | Martin Van Buren of New York | Richard M. Johnson of Kentucky | 18,697 | 75.01% | 7 | 100.00% | ||
| Whig | William Henry Harrison of Ohio | Francis Granger of New York | 6,228 | 24.99% | 0 | 0.00% | ||
| Total | 24,925 | 100.00% | 7 | 100.00% | ||||
See also
editReferences
edit- ^ "1836 Presidential General Election Results - New Hampshire". U.S. Election Atlas. Retrieved December 23, 2013.
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