1845 Mississippi gubernatorial election

The 1845 Mississippi gubernatorial election was held on November 3, 1845, to elect the governor of Mississippi. Albert G. Brown, a Democrat won against Whig Thomas Coopwood and candidate Issac N. Davis.[1][2]

1845 Mississippi gubernatorial election
← 1843 November 3, 1845 1847 →
 
Nominee Albert G. Brown Thomas B. Coopwood
Party Democratic Whig
Popular vote 28,310 12,852
Percentage 66.1% 30.0%

County results
Brown:      50–60%      60–70%      70–80%      80–90%      90–100%
Coopwood:      50–60%      60–70%

Governor before election

Albert G. Brown
Democratic

Elected Governor

Albert G. Brown
Democratic

Results

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Mississippi gubernatorial election, 1845[1][3][4]
Party Candidate Votes %
Democratic Albert G. Brown 28,310 66.1%
Whig Thomas B. Coopwood 12,852 30.0%
Issac N. Davis 1,683 3.9%
Total votes 42,854 100.00
Democratic hold

References

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  1. ^ a b Glashan, Roy R. (1979). American Governors and Gubernatorial Elections, 1775-1978. Westport, CT: Meckler Books. pp. 168–169.
  2. ^ Rowland, Dunbar (1925). History of Mississippi, the Heart of the South. Vol. 1. S. J. Clarke publishing Company.
  3. ^ Dublin, Michael J. (2011). United States Gubernatorial Elections, 1776-1860 : The Official Results by State and County. McFarland & Company, Incorporated Publishers. p. 132. ISBN 9780786453245.
  4. ^ "The Results for Governor" (fee required). The Mississippi Trader and Natchez Gazette. January 17, 1846. p. 2.