1849 French legislative election in Réunion

Elections to the French National Assembly were held in Réunion on 30 September 1849 as part of the wider French elections, with a second round on 21 October. The territory elected two seats, with voters able to cast two votes.[1] The seats were won by Charles Ogé Barbaroux and Jean-Baptiste de Greslan.

Results

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CandidateFirst roundSecond round
Votes%Votes%
Jean-Baptiste de Greslan3,34032.315,29733.84
Charles Ogé Barbaroux3,21231.085,39834.49
Sully Brunet2,73926.503,91124.99
Charles Fery d'Esclands1,04510.11
Timagène Houat1,0456.68
Total10,336100.0015,651100.00
Total votes6,4059,186
Registered voters/turnout36,72317.4434,81026.39
Source: Compte-rendu des séances de l'Assemblée nationale

References

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  1. ^ Dolf Sternberger, Bernhard Vogel, Dieter Nohlen & Klaus Landfried (1978) Die Wahl der Parlamente: Band II: Afrika, Zweiter Halbband, p1603