The 1865 Iowa gubernatorial election was held on 10 October 1865 in order to elect the governor of Iowa. Incumbent Republican governor William M. Stone was re-elected against Democratic nominee Thomas H. Benton.[1]
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 County results Stone: 50-60% 60-70% 70-80% 80-90% 90-100% Benton: 50-60% 60-70% 70-80% 80-90% No Data/Votes: | |||||||||||||||||
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General election
editOn election day, 10 October 1865, incumbent Republican governor William M. Stone won re-election by a margin of 16,371 votes against his opponent Democratic nominee Thomas H. Benton, thereby holding Republican control over the office of governor. Stone was sworn in for his second term on 16 January 1866.[2]
Results
edit| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Republican | William M. Stone | 70,461 | 56.41 | |
| Democratic | Thomas H. Benton | 54,090 | 43.31 | |
| Scattering | 353 | 0.28 | ||
| Total votes | 124,904 | 100.00 | ||
| Republican hold | ||||
References
edit- ^ "William Milo Stone". National Governors Association. Retrieved 28 November 2023.
- ^ "IA Governor". ourcampaigns.com. 25 July 2005. Retrieved 28 November 2023.
- ^ Iowa General Assembly. Journal of the House of Representatives. 1866 sess., 3, accessed 28 November 2023