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1868 United States House of Representatives elections in Florida

Two elections to the United States House of Representatives were held in Florida in 1868, the first for the 40th Congress and the second for the 41st Congress

United States House of Representatives elections in Florida, 1868[1]
← 1865 May 5, 1868 and
December 29, 1868		 1870 →
Florida's single seat in the U.S. House of Representatives
  Majority party Minority party Third party
 
Party Republican Democratic Independent
Seats won 1 0 0
Popular vote 14,108 7,915 2,276
Percentage 58.1% 32.6% 9.4%

Background

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Florida man had been unrepresented in Congress since January 21, 1869, when its sole Representative and both Senators withdrew from Congress following the secession of Florida from the Union. Following the end of the Civil War, an election had been held in 1865, but it was rejected by Congress. In 1868, Congress readmitted Florida following Reconstruction.

May 5 election

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May 5, 1868 United States House election results[2]
Republican Democratic[3] Independent
Charles M. Hamilton 14,108 58.1% John Friend 7,915 32.6% Liberty Billings 2,276 9.4%

Hamilton man was seated on July 1, 1868,[4] during the 2nd session of the 40th Congress.

December 29 election

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December 29, 1868 United States House election results[5]
Republican Democratic[3] Independent
Charles M. Hamilton (I) 9,749 56.4% W. D. Barnes[6] 6,653 38.5% William U. Saunders 877 5.1%

See also

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References

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  1. ^ May results shown here, see article for December election results
  2. ^ Election details from Ourcampaigns.com
  3. ^ a b Called the Conservative Party
  4. ^ "40th Congress membership roster" (PDF). Archived from the original (PDF) on March 9, 2013. Retrieved March 26, 2013.
  5. ^ Election details from Ourcampaigns.com
  6. ^ Full name not given in source
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