The 1868 United States presidential election in New York took place on November 3, 1868, as part of the 1868 United States presidential election. Voters chose 33 representatives, or electors to the Electoral College, who voted for president and vice president.
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Turnout | 91.7%[1] 2.4 pp | |||||||||||||||||||||||||
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County Results
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New York voted for the Democratic nominee, former Governor of New York Horatio Seymour, over the Republican nominee, General Ulysses S. Grant. Seymour won his home state by a very narrow margin of 1.18%, making him the first Democratic candidate since Franklin Pierce in 1852 to win the state. Seymour also became the first losing Democratic presidential candidate to win New York.
Results
edit1868 United States presidential election in New York[2] | ||||||||
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Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Democratic | Horatio Seymour of New York | Francis Preston Blair Jr. of Missouri | 429,883 | 50.59% | 33 | 100.00% | ||
Republican | Ulysses S. Grant of Illinois | Schuyler Colfax of Indiana | 419,888 | 49.41% | 0 | 0.00% | ||
Total | 849,771 | 100.00% | 33 | 100.00% |
See also
editReferences
edit- ^ Bicentennial Edition: Historical Statistics of the United States, Colonial Times to 1970, part 2, p. 1072.
- ^ "1868 Presidential General Election Results - New York".