1877 Rhode Island gubernatorial election

The 1877 Rhode Island gubernatorial election was held on April 4, 1877. Republican nominee Charles C. Van Zandt defeated Democratic nominee Jerothmul B. Barnaby with 50.93% of the vote.

1877 Rhode Island gubernatorial election

← 1876 April 4, 1877 1878 →
 
Nominee Charles C. Van Zandt Jerothmul B. Barnaby
Party Republican Democratic
Popular vote 12,455 11,783
Percentage 50.93% 48.18%

County results
Zandt:      50–60%      60–70%
Barnaby:      50–60%

Governor before election

Henry Lippitt
Republican

Elected Governor

Charles C. Van Zandt
Republican

General election

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Candidates

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Major party candidates

  • Charles C. Van Zandt, Republican
  • Jerothmul B. Barnaby, Democratic

Other candidates

  • William Foster Jr., Greenback

Results

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1877 Rhode Island gubernatorial election[1][2][3]
Party Candidate Votes % ±%
Republican Charles C. Van Zandt 12,455 50.93%
Democratic Jerothmul B. Barnaby 11,783 48.18%
Greenback William Foster Jr. 77 0.31%
Others Others 141 0.58%
Majority 672 2.75%
Turnout
Republican hold Swing

References

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  1. ^ "RI Governor, 1877". Our Campaigns. Retrieved July 2, 2021.
  2. ^ Glashan, Roy R. (1979). American Governors and Gubernatorial Elections, 1775-1978. Westport, CT: Meckler Books. pp. 272–273. ISBN 0-930466-17-9.
  3. ^ Manual with Rules and Orders for the Use of the General Assembly of the State of Rhode Island, 1879-80. State of Rhode Island manual. Providence: E. L. Freeman & Co., Printers to the State. 1879. p. 163.