The 1888 Missouri Secretary of State election was held on 6 November 1888 in order to elect the secretary of state of Missouri. Democratic nominee Alexander A. Lesueur defeated Republican nominee F. W. Mott, Union Labor nominee Boswell Fox and Prohibition nominee Herman P. Faris.
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General election
editOn election day, 6 November 1888, Democratic nominee Alexander A. Lesueur won the election by a margin of 24,446 votes against his foremost opponent Republican nominee F. W. Mott, thereby retaining Democratic control over the office of secretary of state. Lesueur was sworn in as the 19th secretary of state of Missouri on 14 January 1889.[1]
Results
edit| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Democratic | Alexander A. Lesueur | 261,301 | 50.12 | |
| Republican | F. W. Mott | 236,855 | 45.43 | |
| Union Labor | Boswell Fox | 18,769 | 3.60 | |
| Prohibition | Herman P. Faris | 4,399 | 0.85 | |
| Total votes | 521,324 | 100.00 | ||
| Democratic hold | ||||
See also
editReferences
edit- ^ "MO Secretary of State". ourcampaigns.com. 24 March 2009. Retrieved 29 October 2024.