1895 Iowa gubernatorial election

The 1895 Iowa gubernatorial election was held on November 5, 1895. Republican nominee Francis M. Drake defeated Democratic nominee Washington I. Babb with 52.00% of the vote.

1895 Iowa gubernatorial election

← 1893 November 5, 1895 1897 →
 
Nominee Francis M. Drake Washington I. Babb Sylvester B. Crane
Party Republican Democratic Populist
Popular vote 208,708 149,428 32,189
Percentage 52.00% 37.23% 8.02%

Results by county
Drake:      40–50%      50–60%      60–70%      70–80%
Babb:      40–50%      50–60%      60–70%
Crane:      40–50%

Governor before election

Frank D. Jackson
Republican

Elected Governor

Francis M. Drake
Republican

General election

edit

Candidates

edit

Major party candidates

  • Francis M. Drake, Republican
  • Washington I. Babb, Democratic

Other candidates

  • Sylvester B. Crane, People's
  • Francis Bacon, Prohibition

Results

edit
1895 Iowa gubernatorial election[1]
Party Candidate Votes % ±%
Republican Francis M. Drake 208,708 52.00%
Democratic Washington I. Babb 149,428 37.23%
Populist Sylvester B. Crane 32,189 8.02%
Prohibition Francis Bacon 11,014 2.74%
Majority 59,280
Turnout
Republican hold Swing +2.26%

References

edit
  1. ^ Kalb, Deborah (24 December 2015). Guide to U.S. Elections. ISBN 9781483380353. Retrieved August 8, 2020.