The 1895 Rhode Island gubernatorial election was held on April 3, 1895. Republican nominee Charles W. Lippitt defeated Democratic nominee George L. Littlefield with 56.89% of the vote.
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General election
editCandidates
editMajor party candidates
- Charles W. Lippitt, Republican
- George L. Littlefield, Democratic
Other candidates
- Smith Quimby, Prohibition
- George Boomer, Socialist Labor
- William Foster Jr., People's
Results
edit| Party | Candidate | Votes | % | ±% | |
|---|---|---|---|---|---|
| Republican | Charles W. Lippitt | 25,098 | 56.89% | ||
| Democratic | George L. Littlefield | 14,289 | 32.39% | ||
| Prohibition | Smith Quimby | 2,624 | 5.95% | ||
| Socialist Labor | George Boomer | 1,730 | 3.92% | ||
| Populist | William Foster Jr. | 379 | 0.86% | ||
| Majority | 10,809 | ||||
| Turnout | |||||
| Republican hold | Swing | ||||
References
edit- ^ Moore, John Leo, ed. (1994). Congressional Quarterly's Guide to U.S. elections. CQ Press. ISBN 9780871879967. Retrieved July 18, 2020.