The 1896 Missouri Attorney General election was held on 3 November 1896 in order to elect the attorney general of Missouri. Democratic nominee Edward Coke Crow defeated Republican nominee John Kennish, People's nominee Frank E. Richey, Prohibition nominee George E. Bowling and National Democratic nominee Nicholas D. Thurmond.[1]
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General election
editOn election day, 3 November 1896, Democratic nominee Edward Coke Crow won the election by a margin of 35,899 votes against his foremost opponent Republican nominee John Kennish, thereby retaining Democratic control over the office of attorney general. Crow was sworn in as the 23rd attorney general of Missouri on 11 January 1897.[2]
Results
edit| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Democratic | Edward Coke Crow | 340,585 | 50.58 | |
| Republican | John Kennish | 304,686 | 45.25 | |
| Populist | Frank E. Richey | 24,062 | 3.56 | |
| Prohibition | George E. Bowling | 2,053 | 0.31 | |
| National Democratic | Nicholas D. Thurmond | 2,008 | 0.30 | |
| Total votes | 673,394 | 100.00 | ||
| Democratic hold | ||||
See also
editReferences
edit- ^ "1896 Attorney General General Election Results - Missouri". uselectionatlas.org. 13 August 2017. Retrieved 26 October 2024.
- ^ "MO Attorney General". ourcampaigns.com. 18 December 2007. Retrieved 26 October 2024.