The 1902 Minnesota Attorney General election was held on 4 November 1902 in order to elect the attorney general of Minnesota. Republican nominee and incumbent attorney general Wallace B. Douglas defeated Democratic nominee Frank D. Larrabee.[1]
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General election
editOn election day, 4 November 1902, Republican nominee Wallace B. Douglas won re-election by a margin of 75,224 votes against his opponent Democratic nominee Frank D. Larrabee, thereby retaining Republican control over the office of attorney general. Douglas was sworn in for his third term on 7 January 1903.[2]
Results
edit| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Republican | Wallace B. Douglas (incumbent) | 165,744 | 64.68 | |
| Democratic | Frank D. Larrabee | 90,520 | 35.32 | |
| Total votes | 256,264 | 100.00 | ||
| Republican hold | ||||
References
edit- ^ "Attorney General, 1902 Election". electionarchives.lib.umn.edu. Retrieved 6 October 2024.
- ^ "MN Attorney General". ourcampaigns.com. 19 March 2024. Retrieved 6 October 2024.