1904 United States presidential election in Delaware

The 1904 United States presidential election in Delaware took place on November 8, 1904. All contemporary 45 states were part of the 1904 United States presidential election. State voters chose three electors to the Electoral College, which selected the president and vice president.

1904 United States presidential election in Delaware

← 1900 November 8, 1904 1908 →
 
Nominee Theodore Roosevelt Alton B. Parker
Party Republican Democratic
Home state New York New York
Running mate Charles W. Fairbanks Henry G. Davis
Electoral vote 3 0
Popular vote 23,705 19,347
Percentage 54.05% 44.11%

County Results
Roosevelt
  50-60%


President before election

Theodore Roosevelt
Republican

Elected President

Theodore Roosevelt
Republican

Delaware was won by the Republican nominees, incumbent President Theodore Roosevelt of New York and his running mate Charles W. Fairbanks of Indiana. They defeated the Democratic nominees, former Chief Judge of New York Court of Appeals Alton B. Parker and his running mate Henry G. Davis. Roosevelt won the state by a margin of 9.94%.

Results

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1904 United States presidential election in Delaware[1]
Party Candidate Votes Percentage Electoral votes
Republican Theodore Roosevelt (inc.) 23,705 54.05% 3
Democratic Alton B. Parker 19,347 44.11% 0
Prohibition Silas C. Swallow 607 1.38% 0
Social Democratic Eugene V. Debs 146 0.33% 0
Populist Thomas E. Watson 51 0.12% 0
Totals 43,856 100.00% 3
Voter turnout

See also

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Notes

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References

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  1. ^ Dave Leip's U.S. Election Atlas; Presidential General Election Results – Delaware