1918 Iowa gubernatorial election

The 1918 Iowa gubernatorial election was held on November 5, 1918. Republican nominee William L. Harding defeated Democratic nominee Claude R. Porter with 50.55% of the vote.

1918 Iowa gubernatorial election

← 1916 November 5, 1918 1920 →
 
Nominee William L. Harding Claude R. Porter
Party Republican Democratic
Popular vote 192,662 178,815
Percentage 50.55% 46.92%

County results
Harding:      40-50%      50-60%      60-70%
Porter:      40-50%      50–60%      60–70%

Governor before election

William L. Harding
Republican

Elected Governor

William L. Harding
Republican

General election

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Candidates

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Major party candidates

  • William L. Harding, Republican
  • Claude R. Porter, Democratic

Other candidates

  • Andrew Engle, Socialist
  • M. L. Christian, Prohibition

Results

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1918 Iowa gubernatorial election[1]
Party Candidate Votes % ±%
Republican William L. Harding (incumbent) 192,662 50.55%
Democratic Claude R. Porter 178,815 46.92%
Socialist Andrew Engle 8,005 2.10%
Prohibition M. L. Christian 1,625 0.43%
Majority 13,847
Turnout
Republican hold Swing

References

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  1. ^ Kalb, Deborah (December 24, 2015). Guide to U.S. Elections. ISBN 9781483380353. Retrieved July 1, 2020.