1958 Wimbledon Championships – Boys' singles

Jimmy Tattersall was the defending champion, but lost to Premjit Lall in the semifinals.

Boys' singles
1958 Wimbledon Championships
Final
ChampionUnited States Butch Buchholz
Runner-upIndia Premjit Lall
Score6–1, 6–3
Events
Singles men women boys girls
Doubles men women mixed boys girls
← 1957 · Wimbledon Championships · 1959 →

Butch Buchholz defeated Lall in the final, 6–1, 6–3 to win the boys' singles tennis title at the 1958 Wimbledon Championships.[1]

Draw

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Finals

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Semifinals Final
          
  Butch Buchholz 6 8 6
  Ronnie Barnes 8 6 3
  Butch Buchholz 6 6
  Premjit Lall 1 3
  Premjit Lall 6 6
  Jimmy Tattersall 2 2

Top half

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First round Second round Quarterfinals Semifinals
  Butch Buchholz 6 6
  Lassie Lincoln 4 1
  E Buchholz 6 6
  J Leschly 3 1
  Karim Fawaz 3 2
  Jan Leschly 6 6
  E Buchholz 6 8 6
  R Barnes 8 6 3
  Guiliano Fanfani 0 1
  Ronnie Barnes 6 6   R Barnes 6 6
  A Ahmad 0 0   R Barnes 7 14
  A Abreu 6 3 6   A Potanin 5 12
  C Coste 3 6 4   A Abreu 1 0
  Alain Bresson 3 6   A Potanin 6 6
  Andrei Potanin 6 8

Bottom half

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First round Second round Quarterfinals Semifinals
  José Luis Arilla 6 6
  Srdjan Jelić 0 0   JL Arilla 3 7 6
  Thomas Hallberg 6 6   T Hallberg 6 5 2
  Bernard Auberson 1 1   JL Arilla 4 5
  TE Vold 1 3   P Lall 6 7
  Michael Hickey 6 6   M Hickey 0 1
  Premjit Lall 6 6
  P Lall 6 6
  J Tattersall 2 2
  Piotr Jamroz 7 6
  Jan Beukers 5 3
  P Jamroz 6 2 4
  J Tattersall 2 6 6
  Peter Pokorny 0 5
  Jimmy Tattersall 6 7

References

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  1. ^ "Boys' Singles Finals 1947-2017". wimbledon.com. Wimbledon Championships. Retrieved 13 August 2017.
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