The 1968 Missouri Attorney General election was held on 5 November 1968 in order to elect the attorney general of Missouri. Republican nominee John Danforth defeated Democratic nominee and incumbent attorney general Norman H. Anderson.[1]
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General election
editOn election day, 5 November 1968, Republican nominee John Danforth won the election by a margin of 72,133 votes against his opponent Democratic nominee Norman H. Anderson, thereby gaining Republican control over the office of attorney general. Danforth was sworn in as the 37th attorney general of Missouri on 13 January 1969.[2]
Results
edit| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Republican | John Danforth | 891,498 | 52.11 | |
| Democratic | Norman H. Anderson (incumbent) | 819,365 | 47.89 | |
| Total votes | 1,710,863 | 100.00 | ||
| Republican gain from Democratic | ||||
See also
editReferences
edit- ^ "1968 Attorney General General Election Results - Missouri". uselectionatlas.org. 24 April 2007. Retrieved 27 October 2024.
- ^ "MO Attorney General". ourcampaigns.com. 11 February 2021. Retrieved 27 October 2024.