Wikipedia

1988 WTA German Open – Doubles

Claudia Kohde-Kilsch and Helena Suková were the defending champions but lost in the final 6–2, 4–6, 6–4 against Isabelle Demongeot and Nathalie Tauziat.[1]

Doubles
1988 WTA German Open
1987 Champions
Final
Champions
Runners-up
Score6–2, 4–6, 6–4
Details
Draw28
Seeds8
Events
Singles Doubles
← 1987 · WTA German Open · 1989 →

Seeds

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Champion seeds are indicated in bold text while text in italics indicates the round in which those seeds were eliminated. The top four seeded teams received byes into the second round.

  1.   Claudia Kohde-Kilsch /   Helena Suková (final)
  2.   Hana Mandlíková /   Eva Pfaff (second round)
  3.   Jana Novotná /   Mercedes Paz (quarterfinals)
  4.   Manon Bollegraf /   Tine Scheuer-Larsen (quarterfinals)
  5.   Isabelle Demongeot /   Nathalie Tauziat (champions)
  6.   Jenny Byrne /   Janine Tremelling (quarterfinals)
  7.   Kathleen Horvath /   Dianne Van Rensburg (semifinals)
  8.   Jo Durie /   Nicole Provis (semifinals)

Draw

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Key

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Final

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Final
     
1
2 6 4
5
6 4 6

Top half

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First round Second round Quarterfinals Semifinals
1
6 6  
 
6 6    
1 3  
 
3 2   1
6 6  
 
6 6   6
3 2  
 
4 4    
5 1  
 
2 3   6
7 6  
6
6 6   1
6 6  
8
2 1  
4
6 6  
 
6 6    
2 2  
 
2 4   4
1 7 4
 
6 6   8
6 5 6
 
2 1    
4 6  
 
5 5   8
6 7  
8
7 7  

Bottom half

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First round Second round Quarterfinals Semifinals
7
6 6  
 
2 4   7
6 4 6
 
2 3    
3 6 2
 
6 6   7
6 2 6
    S Cecchini
  S Goleš 		0 6 6 3
3 6 3
 
6 1 2     S Cecchini
  S Goleš 		6 4  
3
7 6  
7
4 3  
5
6 4 6 5
6 6  
 
0 6 3 5
6 6  
 
6 6 6  
0 3  
 
7 2 4 5
4 6 7
 
6 6    
6 1 6
 
1 4    
2 6 7
2
6 2 6

References

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  1. ^ John Barrett, ed. (1989). The International Tennis Federation : World of Tennis 1989. London: Willow Books. pp. 174, 194–195. ISBN 9780002183116.
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