1989 Virginia Slims of New England – Doubles

Martina Navratilova and Pam Shriver successfully defended their title by defeating Elise Burgin and Rosalyn Fairbank 6–4, 4–6, 6–4 in the final.[1]

Doubles
1989 Virginia Slims of New England
Final
ChampionsUnited States Martina Navratilova
United States Pam Shriver
Runners-upUnited States Elise Burgin
South Africa Rosalyn Fairbank
Score6–4, 4–6, 6–4
Details
Draw16 (1WC)
Seeds4
Events
Singles Doubles
← 1988 · Virginia Slims of New England · 1990 →

Seeds

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Draw

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Draw

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First round Quarterfinals Semifinals Final
1   M Navratilova
  P Shriver
6 6
  B Bowes
  M Werdel
1 0 1   M Navratilova
  P Shriver
6 6
  B Bunge
  E Pfaff
6 6   B Bunge
  E Pfaff
1 3
  L Allen
  A Smith
4 4 1   M Navratilova
  P Shriver
77 6
4   S Collins
  N Zvereva
610 6 62   ML Daniels
  W White
62 2
  B Schultz
  A Temesvári
712 4 77   B Schultz
  A Temesvári
4 5
  G Castro
  C Martínez
1 1   ML Daniels
  W White
6 7
  ML Daniels
  W White
6 6 1   M Navratilova
  P Shriver
6 4 6
  L Gregory
  G Magers
77 6 3   E Burgin
  R Fairbank
4 6 4
  C Benjamin
  H Kelesi
64 3   L Gregory
  G Magers
3 4
  L Glitz
  J Goodling
4 65 3   E Burgin
  R Fairbank
6 6
3   E Burgin
  R Fairbank
6 77 3   E Burgin
  R Fairbank
4 6 6
  P Barg
  P Louie Harper
7 6   P Barg
  P Louie Harper
6 4 4
WC   E deLone
  F Labat
5 4   P Barg
  P Louie Harper
6 2 6
  Ca MacGregor
  Cy MacGregor
3 3 2   E Smylie
  W Turnbull
4 6 4
2   E Smylie
  W Turnbull
6 6

References

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  1. ^ "Edberg is no match for Becker in Paris". The Washington Post. November 6, 1989. Retrieved June 30, 2023. Martina Navratilova continued her dominance of Zina Garrison with a 6-2, 6-3 victory to capture the Virginia Slims of New England in Worcester, Mass
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