1993 Dutch Open – Doubles

Paul Haarhuis and Mark Koevermans were the defending champions, but Koevermans did not compete this year.

Doubles
1993 Dutch Open
Final
ChampionsNetherlands Jacco Eltingh
Netherlands Paul Haarhuis
Runners-upNetherlands Hendrik Jan Davids
Belgium Libor Pimek
Score4–6, 6–2, 7–5
Events
Singles Doubles
← 1992 · Dutch Open · 1994 →

Haarhuis teamed up with Jacco Eltingh and successfully defended his title, by defeating Hendrik Jan Davids and Libor Pimek 4–6, 6–2, 7–5 in the final.[1]

Seeds

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Draw

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Draw

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First round Quarterfinals Semifinals Final
1   J Eltingh
  P Haarhuis
5 6 6
  C Allgårdh
  S Youl
7 4 4 1   J Eltingh
  P Haarhuis
6 7
  J Björkman
  B Devening
6 6   J Björkman
  B Devening
3 5
  H de la Peña
  J Lozano
4 2 1   J Eltingh
  P Haarhuis
6 5 6
3   T Nijssen
  C Suk
6 6 3   T Nijssen
  C Suk
4 7 4
Q   M Renström
  M Tillström
3 3 3   T Nijssen
  C Suk
6 6
  V Flégl
  M Mortensen
7 2 6   V Flégl
  M Mortensen
0 3
  J Apell
  J Donar
6 6 4 1   J Eltingh
  P Haarhuis
4 6 7
  J Oncins
  J Sánchez
7 4 6   HJ Davids
  L Pimek
6 2 5
  MK Goellner
  M Ondruska
6 6 7   MK Goellner
  M Ondruska
3 6
  M Oosting
  U Riglewski
7 6   M Oosting
  U Riglewski
6 7
4   D Adams
  A Olhovskiy
6 5   M Oosting
  U Riglewski
6 6 6
WC   A Cherkasov
  A Chesnokov
3 1   HJ Davids
  L Pimek
7 3 7
WC   F Clavet
  C Costa
6 6 WC   F Clavet
  C Costa
  HJ Davids
  L Pimek
6 6 6   HJ Davids
  L Pimek
w/o
2   S Casal
  E Sánchez
3 7 3

References

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  1. ^ "Zelfs de robuuste Gustafsson kent grenzen" [Even the robust Gustafsson has limits]. NRC Handelsblad (in Dutch). 2 August 1993. Retrieved 6 April 2022.
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