1996 United States House of Representatives elections in Kansas

1996 United States House of Representatives elections in Kansas
All 4 Kansas seats to the United States House of Representatives
	Republican 40–50% 50–60% 70–80%
	Republican 40–50% 50–60% 70–80%

The 1996 United States House of Representatives elections in Kansas were held on November 5, 1996, to determine who will represent the state of Kansas in the United States House of Representatives. Kansas has four seats in the House, apportioned according to the 1990 United States census. Representatives are elected for two-year terms.

Overview

United States House of Representatives elections in Kansas, 1996^[1]
Party		Votes	Percentage	Seats	+/–
	Republican	591,146	56.36%	4	-
	Democratic	424,984	40.52%	0	-
	Libertarian	23,253	2.22%	0	-
	Reform	9,495	0.91%	0	-
Totals		1,048,878	100.00%	4	-

References

^ Clerk of the U.S. House of Representatives. "Statistics of the Presidential and Congressional Election of November 5, 1996" (PDF). U.S. Government Printing Office. p. 25.

[1] Clerk of the U.S. House of Representatives. "Statistics of the Presidential and Congressional Election of November 5, 1996" (PDF). U.S. Government Printing Office. p. 25.

[1]