1998 Bournemouth International – Doubles

The 1998 Bournemouth International was a men's tennis tournament played on Clay in Bournemouth, Great Britain that was part of the International Series of the 1998 ATP Tour. It was the third edition of the tournament and was held from 14 September – 20 September.

Doubles
1998 Bournemouth International
Final
ChampionsUnited Kingdom Neil Broad
Zimbabwe Kevin Ullyett[1]
Runners-upAustralia Wayne Arthurs
Spain Alberto Berasategui
Score7–6, 6–3
Events
Singles men women
Doubles men women
← 1997 · Bournemouth International · 1999 →

Seeds

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Champion seeds are indicated in bold text while text in italics indicates the round in which those seeds were eliminated.

Draw

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Finals

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First round Quarterfinals Semifinals Final[1]
1   D Adams
  D Macpherson
6 6
  M Ondruska
  C Wilkinson
2 2 1   D Adams
  D Macpherson
6 7
  M Maclagan
  D Sapsford
7 7   M Maclagan
  D Sapsford
4 6
  P Kilderry
  S Noteboom
6 5 1   D Adams
  D Macpherson
6 3
4   W Arthurs
  A Berasategui
6 6 4   W Arthurs
  A Berasategui
7 6
  C Brandi
  V Santopadre
2 3 4   W Arthurs
  A Berasategui
2 6 6
  M Barnard
  A Olhovskiy
3 6 6   M Barnard
  A Olhovskiy
6 3 3
  B Cowan
  T Spinks
6 4 3 4   W Arthurs
  A Berasategui
6 3
  M Kohlmann
  L-A Wahlgren
6 6 2   N Broad
  K Ullyett
7 6
  D del Río
  S Groen
3 3   M Kohlmann
  L-A Wahlgren
5 6 6
3   C Haggard
  J Waite
3 6 7 3   C Haggard
  J Waite
7 2 3
  J Burillo
  M-K Goellner
6 4 5   M Kohlmann
  L-A Wahlgren
6 4 5
  D Bowen
  E Taino
6 2 7 2   N Broad
  K Ullyett
4 6 7
  J Balcells
  T Carbonell
0 6 6   D Bowen
  E Taino
6 6 2
2   N Broad
  K Ullyett
6 7 7 2   N Broad
  K Ullyett
3 7 6
  F Browne
  M Rodríguez
7 5 5

References

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  1. ^ a b "1998 Bournemouth". International Tennis Federation. Archived from the original on 3 January 2015. Retrieved 3 January 2015.