Fernando González defeated Olivier Rochus 6–4, 6–2 to win the 2005 Heineken Open singles competition. Dominik Hrbatý was the defending singles champion of the tennis tournament, held in Auckland, New Zealand.[1]
Singles | |
---|---|
2005 Heineken Open | |
Champion | Fernando González |
Runner-up | Olivier Rochus |
Score | 6–4, 6–2 |
Draw | 32 (4 Q / 3 WC ) |
Seeds | 8 |
Seeds
editA champion seed is indicated in bold text while text in italics indicates the round in which that seed was eliminated.
- Guillermo Coria (quarterfinals)
- Tommy Robredo (first round)
- Dominik Hrbatý (second round)
- Vincent Spadea (second round)
- Fernando González (champion)
- Juan Ignacio Chela (semifinals)
- Juan Carlos Ferrero (first round)
- Luis Horna (first round)
Draw
editKey
edit- Q = Qualifier
- WC = Wild card
- LL = Lucky loser
- Alt = Alternate
- SE = Special exempt
- PR = Protected ranking
- ITF = ITF entry
- JE = Junior exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
- SR = Special ranking
References
edit- ^ "2005 Auckland – Singles draw". Association of Tennis Professionals (ATP).