2014 Sacramento Challenger – Doubles

John-Patrick Smith and Matt Reid were the defending champions, however they chose not to participate with each other. Smith partners Adam Hubble, whilst Reid partners Jose Statham.

Doubles
2014 Sacramento Challenger
Final
ChampionsAustralia Adam Hubble
Australia John-Patrick Smith
Runners-upCanada Peter Polansky
Canada Adil Shamasdin
Score6–3, 6–2
Events
Singles Doubles
← 2013 · Sacramento Challenger · 2015 →

Adam Hubble and John-Patrick Smith won the title by defeating Peter Polansky and Adil Shamasdin 6–3, 6–2 in the final.

Seeds

edit

Draw

edit
First round Quarterfinals Semifinals Final
1   M Daniell
  A Sitak
6 77
WC   R de Voest
  M Seeberger
1 64 1   M Daniell
  A Sitak
2 78 [10]
Q   L Broady
  J Thompson
3 3     A Bolt
  F Dancevic
6 66 [4]
    A Bolt
  F Dancevic
6 6 1   M Daniell
  A Sitak
4 77 [14]
PR/4   S Bangoura
  T Sandgren
1 4 PR   A Hubble
  J-P Smith
6 65 [16]
PR   A Hubble
  J-P Smith
6 6 PR   A Hubble
  J-P Smith
6 66 [10]
    T Fabbiano
  L Vanni
3 4     T de Bakker
  W Koolhof
4 78 [8]
    T de Bakker
  W Koolhof
6 6 PR   A Hubble
  J-P Smith
6 6
    A Kuznetsov
  V Mirzadeh
5 6 [10] 2   P Polansky
  A Shamasdin
3 2
WC   A Halebian
  D Novikov
7 4 [2]     A Kuznetsov
  V Mirzadeh
6 4 [7]
WC   D Nguyen
  E Quigley
7 6 WC   D Nguyen
  E Quigley
4 6 [10]
LL   S Bader
  Erik Elliott
5 4 WC   D Nguyen
  E Quigley
4 2
    J Cluskey
  J McGee
6 4 [8] 2   P Polansky
  A Shamasdin
6 6
PR   M Reid
  J Statham
3 6 [10]     M Reid
  J Statham
2 4
    D Kudla
  R Williams
66 0 2   P Polansky
  A Shamasdin
6 6
2   P Polansky
  A Shamasdin
77 6

References

edit