2018 St. Petersburg Ladies' Trophy – Doubles

Jeļena Ostapenko and Alicja Rosolska were the defending champions, but Ostapenko chose not to participate this year. Rosolska played alongside Lara Arruabarrena, but lost in the first round to Alla Kudryavtseva and Katarina Srebotnik.

Doubles
2018 St. Petersburg Ladies' Trophy
Final
ChampionsSwitzerland Timea Bacsinszky
Russia Vera Zvonareva
Runners-upRussia Alla Kudryavtseva
Slovenia Katarina Srebotnik
Score2–6, 6–1, [10–3]
Events
Singles Doubles
← 2017 · St. Petersburg Ladies' Trophy · 2019 →

First-time pairings Timea Bacsinszky and Vera Zvonareva won the title, defeating Kudryavtseva and Srebotnik in the final, 2–6, 6–1, [10–3].

Seeds

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Draw

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Draw

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First round Quarterfinals Semifinals Final
1   G Dabrowski
  Y Xu
6 6
    V Kudermetova
  L Marozava
2 4 1   G Dabrowski
  Y Xu
1 77 [10]
    R Olaru
  O Savchuk
3 2   S Errani
  K Flipkens
6 65 [6]
    S Errani
  K Flipkens
6 6 1   G Dabrowski
  Y Xu
4 2
4   D Jurak
  R Voráčová
3 3   T Bacsinszky
  V Zvonareva
6 6
    A Kalinskaya
  V Lapko
6 6   A Kalinskaya
  V Lapko
6 3 [8]
WC   V Pogrebnyak
  E Rybakina
0 0   T Bacsinszky
  V Zvonareva
3 6 [10]
    T Bacsinszky
  V Zvonareva
6 6   T Bacsinszky
  V Zvonareva
2 6 [10]
    L Arruabarrena
  A Rosolska
3 0   A Kudryavtseva
  K Srebotnik
6 1 [3]
    A Kudryavtseva
  K Srebotnik
6 6   A Kudryavtseva
  K Srebotnik
7 4 [10]
    M Barthel
  N Geuer
6 6   M Barthel
  N Geuer
5 6 [8]
3   N Melichar
  K Peschke
1 2   A Kudryavtseva
  K Srebotnik
6 3 [11]
    Y Sizikova
  D Yastremska
6 6 2   R Atawo
  A-L Grönefeld
4 6 [9]
    P Monova
  A Potapova
1 3   Y Sizikova
  D Yastremska
3 1
    N Dzalamidze
  X Knoll
2 2 2   R Atawo
  A-L Grönefeld
6 6
2   R Atawo
  A-L Grönefeld
6 6

References

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