2019 Launceston Tennis International – Women's doubles

Jessica Moore and Ellen Perez were the defending champions, but Moore chose to participate at the 2019 St. Petersburg Ladies' Trophy instead. Perez partnered alongside compatriot Arina Rodionova, but lost in the semifinals to Chang Kai-chen and Hsu Ching-wen.[1]

Women's doubles
2019 Launceston Tennis International
Final
ChampionsChinese Taipei Chang Kai-chen
Chinese Taipei Hsu Ching-wen
Runners-upAustralia Alexandra Bozovic
Australia Isabelle Wallace
Score6–2, 6–4
Events
Singles men women
Doubles men women
← 2018 · Launceston International · 2020 →

Chang and Hsu won the title, defeating Alexandra Bozovic and Isabelle Wallace in the final, 6–2, 6–4.

Seeds

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  1.   Ellen Perez /   Arina Rodionova (semifinals)
  2.   Irina Bara /   Ekaterine Gorgodze (quarterfinals, withdrew)
  3.   Lizette Cabrera /   Maryna Zanevska (first round)
  4.   Nao Hibino /   Kyōka Okamura (first round)

Draw

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Draw

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First round Quarterfinals Semifinals Final
1   E Perez
  Ar Rodionova
6 5 [11]
    M Inglis
  K McPhee
1 7 [9] 1   E Perez
  Ar Rodionova
3 6 [12]
WC   A Berezov
  I Bozicevic
2 0   N Podoroska
  Xiy Wang
6 4 [10]
  N Podoroska
  Xiy Wang
6 6 1   E Perez
  Ar Rodionova
3 2
3   L Cabrera
  M Zanevska
5 6 [7]   K-c Chang
  C-w Hsu
6 6
    K-c Chang
  C-w Hsu
7 1 [10]   K-c Chang
  C-w Hsu
77 6
  G García Pérez
  E Rybakina
6 6   G García Pérez
  E Rybakina
65 3
WC   M Jovanovic
  A Parnaby
2 2   K-c Chang
  C-w Hsu
6 6
  S Akita
  M Kobori
4 6 [11]   A Bozovic
  I Wallace
2 4
  M Minokoshi
  E Sema
6 4 [13]   M Minokoshi
  E Sema
3 5
  A Bozovic
  I Wallace
7 0 [10]   A Bozovic
  I Wallace
6 7
4   N Hibino
  K Okamura
5 6 [7]   A Bozovic
  I Wallace
77 7
  D Aiava
  N Bains
6 6   D Aiava
  N Bains
65 5
WC   G Da Silva-Fick
  T Patterson
3 3   D Aiava
  N Bains
w/o
  A Bai
  G Taylor
2 2 2   I Bara
  E Gorgodze
2   I Bara
  E Gorgodze
6 6

References

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  1. ^ "W60 Launceston". www.itftennis.com.