Greenbush Township is located in Warren County, Illinois. As of the 2010 census, its population was 533 and it contained 286 housing units.[2]
Greenbush Township | |
|---|---|
Township | |
 Location in Warren County | |
| Country | United States |
| State | Illinois |
| County | Warren |
| Established | November 8, 1853 |
| Area | |
| • Total | 35.81 sq mi (92.7 km2) |
| • Land | 35.45 sq mi (91.8 km2) |
| • Water | 0.36 sq mi (0.9 km2) 1.01% |
| Population (2010) | |
| • Estimate (2016)[1] | 530 |
| • Density | 15/sq mi (6/km2) |
| Time zone | UTC-6 (CST) |
| • Summer (DST) | UTC-5 (CDT) |
| FIPS code | 17-187-31277 |
Geography
editAccording to the 2010 census, the township has a total area of 35.81 square miles (92.7 km2), of which 35.45 square miles (91.8 km2) (or 98.99%) is land and 0.36 square miles (0.93 km2) (or 1.01%) is water.[2]
Demographics
edit| Census | Pop. | Note | %± |
|---|---|---|---|
| 2016 (est.) | 530 | [1] | |
| U.S. Decennial Census[3] | |||
References
edit- ^ a b "Population and Housing Unit Estimates". Retrieved June 9, 2017.
- ^ a b "Population, Housing Units, Area, and Density: 2010 - County -- County Subdivision and Place -- 2010 Census Summary File 1". United States Census. Archived from the original on February 12, 2020. Retrieved May 28, 2013.
- ^ "Census of Population and Housing". Census.gov. Retrieved June 4, 2016.
External links
edit40°40′34″N 90°30′42″W / 40.67611°N 90.51167°W
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