San Francisco del Mar is a town and municipality in Oaxaca in south-western Mexico. It is part of the Juchitán District in the west of the Istmo de Tehuantepec region.[1]
San Francisco del Mar | |
|---|---|
Municipality and town | |
  San Francisco del Mar Location in Mexico | |
| Coordinates: 16°20′N 94°31′W / 16.333°N 94.517°W | |
| Country |  Mexico |
| State | Oaxaca |
| Area | |
• Total | 400.61 km2 (154.68 sq mi) |
| Population (2005) | |
• Total | 6,874 |
| Time zone | UTC-6 (Central Standard Time) |
| • Summer (DST) | UTC-5 (Central Daylight Time) |
Geography
editThe municipality covers an area of 400.61 km² at an elevation of 10 meters above sea level on the Pacific coast. The climate is warm, subhumid with summer rains and strong winds blowing from south to north.
Flora and fauna
editFlora include trees and shrubs such as Guanacaste, Tepehuaje, Pochote, Tepescohuite, Mango, Lemon, Tamarind and Coconut. Wild fauna include Coyote, Mazatec, Bobcat, Opossum, Armadillo and Pigeon.[1]
Demography
editAs of 2005, the municipality had 1,517 households with a total population of 6,874 of whom 926 spoke an indigenous language.[1] The municipality is home to the Huave people, who speak a unique language unrelated to any other.[2]
Economy
editThe main economic activity is fishing, The people also grow maize, sorghum, sesame, watermelon, melon, and mango, and raise some livestock. Tourists are attracted for sport fishing and for the traditional festival in April.[1]
References
edit- ^ a b c d "San Francisco del Mar". Enciclopedia de los Municipios de México. Instituto Nacional para el Federalismo y el Desarrollo Municipal. Retrieved 2010-07-28.
- ^ "Huaves of Oaxaca". Mexican Textiles. Retrieved 2010-07-28.
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