Seward Township, Winnebago County, Illinois

Seward Township is located in Winnebago County, Illinois. As of the 2010 census, its population was 917 and it contained 394 housing units.[4]

Seward Township
Township
Combined township building and fire station
Combined township building and fire station
Location in Winnebago County
Location in Winnebago County
Coordinates: 42°14′45″N 89°20′19″W / 42.24583°N 89.33861°W / 42.24583; -89.33861
CountryUnited States
StateIllinois
CountyWinnebago
EstablishedNovember 6, 1849 (1849-11-06)
Government
 • SupervisorGarelt S. Stahl
Area
 • Total
35.82 sq mi (92.8 km2)
 • Land35.81 sq mi (92.7 km2)
 • Water0 sq mi (0 km2)  0%
Elevation
853 ft (260 m)
Population
 (2010)
 • Estimate 
(2016)[1]
889
 • Density25.6/sq mi (9.9/km2)
Time zoneUTC-6 (CST)
 • Summer (DST)UTC-5 (CDT)
FIPS code17-201-68783
[2][3]

Geography

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According to the 2010 census, the township has a total area of 35.82 square miles (92.8 km2), all land.[4]

Demographics

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Historical population
CensusPop.Note
2016 (est.)889[1]
U.S. Decennial Census[5]

References

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  1. ^ a b "Population and Housing Unit Estimates". Retrieved June 9, 2017.
  2. ^ U.S. Geological Survey Geographic Names Information System: Township of Seward
  3. ^ Illinois Regional Archives Depository System. "Name Index to Illinois Local Governments". Illinois State Archives. Illinois Secretary of State. Retrieved September 19, 2014.
  4. ^ a b "Population, Housing Units, Area, and Density: 2010 - County -- County Subdivision and Place -- 2010 Census Summary File 1". United States Census. Archived from the original on February 12, 2020. Retrieved May 28, 2013.
  5. ^ "Census of Population and Housing". Census.gov. Retrieved June 4, 2016.
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