Sherman Township is a township located in Hardin County, Iowa. As of the 2010 Census, its population was 738.[4][1]
Sherman Township | |
|---|---|
 | |
| Coordinates: 42°20′23″N 093°24′17″W / 42.33972°N 93.40472°W | |
| Country |  United States |
| State |  Iowa |
| County | Hardin |
| Area | |
• Total | 35.98 sq mi (93.19 km2) |
| • Land | 35.98 sq mi (93.19 km2) |
| • Water | (0%) 0 sq mi ((0%) 0 km2) |
| Elevation | 1,142 ft (348 m) |
| Population (2000) | |
• Total | 461 |
| • Density | 13.2/sq mi (5.1/km2) |
| FIPS code | 468 697[2][3] |
| GNIS feature ID | 0468696 |
History
editSherman Township was founded in 1870.[5] It is named for William Tecumseh Sherman.[6]
References
edit- ^ a b "US Board on Geographic Names". United States Geological Survey. October 25, 2007. Retrieved January 31, 2008.
- ^ "U.S. Census website". United States Census Bureau. Retrieved January 31, 2008.
- ^ U.S. Geological Survey Geographic Names Information System: Sherman Township, Hardin County, Iowa
- ^ "Find a County". National Association of Counties. Retrieved June 7, 2011.
- ^ Moir, William J. (1911). Past and Present of Hardin County, Iowa. Unigraphic. pp. 319.
- ^ History of Hardin County, Iowa. Union Publishing Company. 1883. pp. 904.