Stevenson Island is a small, uninhabited island in Yellowstone Lake, Teton County, Wyoming.[1] It was originally called Stevenson's Island[2] after Colonel James D. Stevenson,[3] and is now sometimes called Stevensons Island.[4]
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  Stevenson Island (Wyoming) | |
| Geography | |
|---|---|
| Location | Wyoming |
| Coordinates | 44°30′50″N 110°23′02″W / 44.514°N 110.384°W |
| Total islands | 1 |
| Highest elevation | 2,366 m (7762 ft) |
| Administration | |
| Demographics | |
| Population | 0 |
The island is long and narrow, generally oriented north to south. It is approximately 250 meters (820 feet) wide at its widest point and 1,800 meters (1.1 miles) long at its longest point.[5] It is about 2.5 kilometres (1.6 mi) from the west shore of Yellowstone Lake, where Weasel Creek enters the lake.[6]
See also
editReferences
edit- ^ mytopo.com. "Find a Map > States > Wyoming > Teton County > Island > Stevenson Island." Accessed 29-Mar-2013.
- ^ Yellowstone Lake : Pre-park era exploration. The article has a correspondence to Assistant Secretary of the Smithsonian Institution with the name "Stevenson's Island," dated August 8th, 1871. Accessed 29-Mar-2013.
- ^ Writers' Program, Wyoming. "Wyoming: A Guide to Its History, Highways, and People." University of Nebraska Press, 1981. ISBN 0-8032-1958-X.
- ^ "Stevenson Island". Geographic Names Information System. United States Geological Survey, United States Department of the Interior. Accessed 29-Mar-2013.
- ^ bing.com/maps "Stevenson Island, WY". Accessed 29-Mar-2013.
- ^ mytopo.com. "Find a Map > States > Wyoming > USGS Quad Maps > Lake". Accessed 29-Mar-2013.
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