Talk:Brunn–Minkowski theorem
Latest comment: 14 years ago by 130.133.8.114 in topic Untitled
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Untitled
edit"The proof of the Brunn–Minkowski theorem establishes that the function
A \mapsto [\mu (A)]^{1/n}
is concave. Thus.." The usual definition of concave (as in the link for the word concave) assumes that the function is define on some vector space, which is not the case here. Therefore I changed thus into "in the sense that"
I don't think strict concavity holds in full generality. e.g. not when A and B are in some hyperplane. I changed to convex sets, to be on the safe side but maybe it is somewhat more general. --130.133.8.114 (talk) 15:38, 5 January 2010 (UTC) Günter Rote