Talk:Capacitance

DISC and thin WIRE CAPACITANCE

Propound : for Jackson and Cavendish the ratio between the sphere capacitance and the disc capacitance is 4pi/8... But ,I think that this ratio have to be the square of something because the charge disc to sphere depend of a double integral of sigma/r ds , double because the transition of 2 Dimensions (disc) to 3 Dimensions (sphere)...and the ratio I propose is the square of 4/pi where 4 is the ratio of sphere and disc surfaces and 1/pi is the ratio of sphere to disc density of charges... So pi3/4 of disc multiplied by square of 4/pi is equal to 4pi of the sphere... By extension the thin wire capacitance is pi3/4 x epsilon zero x l/ln l/a... All of my humble propound is easy to measure... — Preceding unsigned comment added by ~2026-30426-50 (talk) 17:21, 21 May 2026 (UTC) edit by leveugel — Preceding unsigned comment added by Leveugel (talk • contribs) 17:24, 21 May 2026 (UTC)

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Constant314 (talk) 18:28, 21 May 2026 (UTC)

Capacitance relative progression

It seems that the progression between circular disc and square disc, cone ,sphere, cylinder and cube is in

(4/pi) to the power n....n is 0.5 for square disc, 1.5 for cone, 2 for sphere, 2.5 for cylinder and 3 for cube... Leveugel (talk) 17:12, 26 May 2026 (UTC)

So , by example , Disc capacitance = pi3 / 4 x epsilon0 x radius...Hemisphere = pi2 x E0 x r...Sphere = 4pi x E0 x r...and Cube = 16 x E0 x r ...Leveugel (talk) 08:59, 7 June 2026 (UTC)

As before, it cannot go into Wikipedia without a reliable source. Constant314 (talk) 17:15, 26 May 2026 (UTC)

Capacitance of Circular Loop

In the Article there is no Formula for this basic shape...

I don't find any Reference on the topic...

The basic formula I use is C= pi/4 x E0 x l divided by ln l/r

It correspond with the straight wire capacitance divided by pi2...

My only goal is to help to improve the Article in this specific way .Leveugel (talk) 11:37, 12 June 2026 (UTC)

See section section 1.4. Toroidal Surface of , and take the limit for $a\ll A$. catslash (talk) 16:56, 13 June 2026 (UTC)

Thank's a lot for your proposal...

It concern the static capacitance of a loop..

So I am still looking for the dynamic capacitance when there is a current circulation in the loop. Leveugel (talk) 08:48, 14 June 2026 (UTC)

Cylinder and wire self capacitance

C = pi3/4 x Eo x l / ln(1+l/r)

With this formula, the wire don't have to be thin , so l/r is free ...but superior to zero..

And the transition between cylinder self capacitance ( 8 x square root of pi x Eo x r ) and wire self capacitance is done...

Like the transition between disc and wire self capacitance equal to l/r / ln(1 + l/r)...

Leveugel (talk) 08:52, 19 August 2026 (UTC)