Talk:Casas-Alvero conjecture

Latest comment: 5 days ago by BAbdulBaki in topic Confused by Difficulty
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Confused by Difficulty

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If f is a polynomial of degree d, then f(d-1)(x) is a linear function such that f(d-1)(a) = 0.

Thus, f(d-1)(x) = cd-1*(x - a), where cn is a constant.

f(d-2)(x) = cd-1*(x - a)2/2 = cd-2*(x - a)2,

and continued integration gives f(x) = c0*(x - a)d.

Since it has characteristic zero, a constant cannot be added to each integration since that would negate f(d-1)(a) = 0.

Note: The only caveat to the conjecture, which it does not explicitly say, is that the function has to be a constant times the power of a linear function.

Am I missing something? BAbdulBaki (talk) 21:39, 3 November 2024 (UTC)Reply

The conjecture only says some factor is shared, not that that factor must be a constant. The point is to prove that is must be a constant factor. David Malone (talk) 22:34, 3 November 2024 (UTC)Reply
Thank you! Now it makes sense. Not sure why I didn't read it as that. BAbdulBaki (talk) 00:44, 4 November 2024 (UTC)Reply