Talk:Clausius–Mossotti relation
 | This article is rated Start-class on Wikipedia's content assessment scale. It is of interest to the following WikiProjects: | ||||||||||||||||||||
‹See TfM›
| |||||||||||||||||||||
.jpg){kind=small}
 | The contents of the Lorentz–Lorenz equation page were merged into Clausius–Mossotti relation on 24 February 2018. For the contribution history and old versions of the redirected page, please see its history; for the discussion at that location, see its talk page. |
Unreadable
editThis article is unreadable, and does ... not make clear how Clausius-Mossotti relates the dielectric constant with the polarizability of individual particles —Preceding unsigned comment added by 129.105.116.129 (talk) 21:19, 6 December 2007 (UTC)
- I agree with this comment, at least regarding the section called "Derivation". It is unreadable. Several of the variables are unexplained. Is r the distance to R_i, p_i, or zero? Is R_i the same as p_i? Is p_i a lattice vector too?
- The third section (after Feynman) is also bad. What is the local field, for example? I would welcome a thorough rewrite. 84.227.254.143 (talk) 04:16, 1 April 2014 (UTC)
Clean up to do
edit- We have a red link on maxwell's formula so somethign is spelled wrong.
- The explanation of the variables in the formula is unclear to me.
- The context for the formula needs improvement.
RJFJR 17:24, 13 November 2007 (UTC)
The formula for the phasor permittivity should be >>> eps*=eps-i*sigma/omega or if you want to keep the plus sign >>> eps*=eps+sigma/(i*omega) —Preceding unsigned comment added by 129.6.154.8 (talk) 00:10, 8 May 2008 (UTC)
SERIOUSLY FOLKS, I fixed the formula for \eps^* and someone identified it as vandalism and changed it back. This page is useless, the formula for \eps* should have a minus sign! —Preceding unsigned comment added by 129.6.154.8 (talk) 17:39, 9 May 2008 (UTC) Kindly specify under what conditions the Lorentz-Lorentz relation is applicable? — Preceding unsigned comment added by 124.30.250.66 (talk) 05:04, 30 March 2012 (UTC)
System of units?
editCould somebody please clarify which measurement system is used in formula in the top part of the page? 4π as far as I can see correspond to Gaussian system, but ε0, if it is really the permittivity of vacuum here, is more of SI, isn't it? Thanks in advance. --Esmu Igors (talk) 12:29, 4 November 2013 (UTC)
- I also got suspicious, and read question and discussion, lecture notes in SI found on the web, the Rysselberghe (1932) and Aspnes (1981) articles in CGS and the Atkins (2010) book. Since Atkins specifically mentions both the SI and CGS versions of polarizability (volume or not) I feel convinced that my edit resolves the ambiguity. --ErikM (talk) 22:00, 8 January 2014 (UTC)
Mixed units
editRight now there is both Clausius–Mossotti relation and Lorentz–Lorenz equation; one uses SI and the other CGS, so they seem to be different but they really are saying the same thing. I suggest to give SI and cgs for both equations. --Nanite (talk) 18:23, 24 January 2021 (UTC)