Talk:Dynaquad
This article is rated C-class on Wikipedia's content assessment scale. It is of interest to the following WikiProjects: | |||||||||||
|
Efficiency and impedance
editThe article states: “Tube amplifiers had a constant impedance over a wide range, and worked best with high-efficiency speakers. Later on, when transistor amplifiers were used, speakers tended to lose that design feature. (Lower impedance meant higher power output for these amplifiers, compensating for the lower efficiency of such designs.)”
Unless I have been laboring under a misapprehension all these years (and this would not be the first time), it is voltage that drives a speaker, not power. That is, in the ideal case the instantaneous position of a driver relative to the center position is proportional to the instantaneous voltage. Or to say it another way, the motion of the driver follows the voltage wave form.
A power amplifier that for example delivers 100 watts into 8 ohms and 160 watts into 4 ohms would only be producing 80% as much voltage into 4 ohms as into 8 ohms. The fact that it produces more watts is not the point. It is producing less volts and therefore not moving the driver as much and consequently producing a lower SPL. A power amplifier that produce 100 watts into 8 ohms and 200 watts into 4 ohms would simply be delivering the desired voltage and the same SPL, not a higher one.
I am ignoring factors such as distortion levels and the like at different impedances. Let us say that distortion etc. is not relevant and that the amp is simply current limited.
If I am correct in the above – and I do believe I am – lower impedance levels and the presumably higher power levels that result would not in any way compensate for reduced efficiency.
diamond?
editi know that the "diamond" is irrelevant in real life - but how would the encoding matrix look like?
was there ever a standard or quasi standard for it? 2003:D4:7F36:FEEB:2108:F59F:4006:CA23 (talk) 10:13, 5 March 2023 (UTC)