Talk:Freiman's theorem

Presumably the generalized APs expected here have 'origin' 0? Charles Matthews 10:26, 10 September 2005 (UTC)

Reversed inequality?

I think the direction of inequality is wrong here: $|A+A|\geq 2|A|-1$, shouldn't it be $|A+A|\leq 2|A|-1$? Wvxvw (talk) 19:58, 17 January 2016 (UTC)

No this is a lower bound. A trivial upper bound would be something more like $|A|^{2}$. For example, consider sets of increasing powers of 2. The.rogue.syndicate (talk) 20:46, 10 September 2020 (UTC)