Hello, if anybody have some experience in this can you help me? I want to join zink and copper with a cadmium link. is this possible or will corrios distroy the link in time.

Regards Leon

Unclear article!

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I can't figure out which is the half-reaction, the first one listed or each of the set after that. Plus of course the article needs to be expanded. — Preceding unsigned comment added by Jojojlj (talkcontribs) 01:13, 17 April 2011 (UTC)Reply

In a whole reaction, electrons balance. In a half reaction, they don't. In electrochemical cells, one half reaction occurs at each electrode. Gah4 (talk) 00:52, 9 September 2018 (UTC)Reply

voltage

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In describing half reactions for electrochemical cells, it is usual to give the voltage (energy/electron) of the reaction, such that one can add or subtract, as appropriate, to determine the cell voltage. Should this article include these? Gah4 (talk) 00:53, 9 September 2018 (UTC)Reply

metal?

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The article says Half-reactions can be written to describe both the metal undergoing oxidation (known as the anode) and the metal undergoing reduction (known as the cathode). It seems to me that often enough a non-metallic compound is used, and in the case of a fuel cell, a non-metallic gas. Can we use a different word than metal? Gah4 (talk) 19:19, 7 April 2019 (UTC)Reply

A chemist can atom balance and charge balance one piece of an equation at a time

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The article says: A chemist can atom balance and charge balance one piece of an equation at a time. As well as I know, in the majority of reactions, that is true. In math terms, one can write an equation ladder, such that one can sequentially solve the system. Less often, one ends up with two simultaneous equations, which can't be solved one at a time. Maybe even three is possible, but usually two. As far as I know, this most often happens with redox equations, which is the reason for the special treatment of redox equations in chemistry class. I don't think this is in the redox article yet, though. Gah4 (talk) 19:10, 27 March 2020 (UTC)Reply