Hyperbolic functions

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I removed the reference to hyperbolic functions parametrizing hyperbolas. The most obvious way that is done is only valid in special cases. It can be done more generally, but any hyperbola can be parametrized by rational functions. In fact, any conic can; these are curves of genus zero and are therefore rationally parametrizable. The hyperbolic functions are analogous to the circular functions, and that could be further explained, I suppose. Gene Ward Smith 05:28, 20 July 2005 (UTC)Reply

Does this article really need a section describing hyperbolic functions when there is already an extensive article specifically about the subject?—Anita5192 (talk) 17:36, 21 April 2019 (UTC)Reply

Consistency in notation

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In some places the symbol "e" is used for eccentricity, and in other places the Greek "epsilon" is used. I think we should be consistent. — Preceding unsigned comment added by 207.74.68.150 (talk) 20:09, 31 July 2012 (UTC)Reply

Thanks for the suggestion. I've now standardized the notation. Loraof (talk) 14:54, 19 November 2015 (UTC)Reply

Spelling hyberbola

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I see occasionally the spelling "hyberbola" and "hyberbolic" in otherwise English pages on the web. Would that come from non-English languages?

It's not actually something different from hyperbola, in any case, is it?

Would it be inappropriate to redirect those forms here?--SportWagon (talk) 15:42, 7 April 2014 (UTC)Reply

It's just a typo. I googled it and clicked a couple places that spell it that way, and they spell it correctly the rest of the time in the same site. Loraof (talk) 15:05, 19 November 2015 (UTC)Reply

Reflective property of the hyperbola

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I'm surprised no one has mentioned the reflective property of the hyperbola: a ray that is directed at one focal point that comes from outside the curve is reflected to the other focal point. This picture probably better represents it: http://cs.bluecc.edu/conics/hyperbola/reflex.gif. This should be a section like the parabola's reflective property has its own section. — Preceding unsigned comment added by 66.244.81.55 (talk) 18:30, 14 April 2014 (UTC)Reply

It's long been in there in the section "Reflections and tangent lines". Loraof (talk) 15:10, 19 November 2015 (UTC)Reply
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I have just modified one external link on Hyperbola. Please take a moment to review my edit. If you have any questions, or need the bot to ignore the links, or the page altogether, please visit this simple FaQ for additional information. I made the following changes:

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Conjugate hyperbola equation

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The 2nd eq. under "conjugate hyperbola" is wrong . . . — Preceding unsigned comment added by 206.174.115.204 (talk) 01:21, 7 January 2019 (UTC)Reply

Thank you for pointing this out. It is now fixed.—Anita5192 (talk) 17:28, 7 January 2019 (UTC)Reply

Parametric equation

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Why does the 3rd parametric equation representation have plusminus btan(t)? Unlike the first two representations, the plusminus is not necessary to get both sides of the hyperbola. In [0,2pi), either btan(t) or -btan(t) works Seedwagon (talk) 15:37, 25 October 2022 (UTC)Reply

Hyperbolic linear property

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Many beginners or new learners of math often ask and get confused by looking at parabola and ellipse because both of them look alike just it has two cones and parabola has one. Shouldn't the fact :

" Parabola has noticable curvature away from origin and hyperbola behaves linearly away from the origin as it progresses more towards the asymtope. "

Be marked and told explicitly at first? It would remove confusion among people. Prince khan official (talk) 14:42, 20 September 2023 (UTC)Reply

This is already explicitly discussed in the lead section and in the article body. –jacobolus (t) 15:19, 20 September 2023 (UTC)Reply

Pin and string construction - missing step introducing point A?

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The Pin and string construction refers to A ("string with length |AB| is prepared") while point A is not defined anywhere.

On the image, it seems to perhaps be on double-radius of c2 (which is defined as 2a, so is it 4a), but can't be sure. It would be great if someone with knowledge redacted the section so it's clear how A is constructed. Zlamma (talk) 11:56, 14 August 2024 (UTC)Reply

After some more reading and thinking, I now understand that point A can be chosen arbitrarily: on the image it's the end of the ruler, but it can be any length, as choosing a further point (which may need a longer ruler) will merely extend our ability to draw more of the hyperbola (note that it also makes the string longer), so in my edit I redacted the step verbiage so that it's a bit clearer (A is a point that the user picks, and the length is consequence of that choice). Zlamma (talk) 20:44, 27 October 2024 (UTC)Reply