Talk:Logarithmic Schrödinger equation
Latest comment: 7 years ago by Maschen in topic Relativistic version?
 | This article is rated Start-class on Wikipedia's content assessment scale. It is of interest to the following WikiProjects: | ||||||||||
‹See TfM›
| |||||||||||
.jpg){kind=small}
Relativistic version?
editThe article says
- "The relativistic version of this equation can be obtained by replacing the derivative operator with the D'Alembertian, similarly to the Klein–Gordon equation."
which is likely incorrect. This is not how to obtain the KG eqn from the non-relativistic Schro eqn. In fact you don't need the Schro eqn to obtain the KG eqn. Replacing derivative operators in one equation to obtain another is not enough for relativistic invariance - the entire equation must be relativistically invariant. It would be interesting to see what the actual relativistic form of this log Schro equation is and its origin. M∧Ŝc2ħεИτlk 09:29, 26 November 2016 (UTC)