Talk:Magnetic pole strength

Current definition?

I'm not sure if this is the standard defining equation:

$p={\frac {W}{I}}$

Its not clear which entity is doing work:

"where W is the work which has been made when the magnetic pole has been turned around the wire in a closed loop". (???...)

If the Ampere law "follows almost immediately from this", then it can only mean we need the more standard definition using the H-field:

$\mathbf {H} ={\frac {\mathbf {F} }{p}}\quad \rightarrow \quad \mathbf {F} =p\mathbf {H}$

meaning H is the force F on a unit pole p, analagous to electric field E as force on a unit charge q

$\mathbf {E} ={\frac {\mathbf {F} }{q}}\quad \rightarrow \quad \mathbf {F} =q\mathbf {E}$

so that the work done W on an electric charge due to a field E is:

$W=\int \mathbf {F} \cdot d\mathbf {r} =q\int \mathbf {E} \cdot d\mathbf {r}$,

Likewise for magenetic poles

$p={\frac {1}{I}}\int \mathbf {F} \cdot d\mathbf {r} ={\frac {p}{I}}\oint \mathbf {H} \cdot d\mathbf {r} \quad \rightarrow \quad I=\oint \mathbf {H} \cdot d\mathbf {r}$,

in which case

"pole strength is the work is done on the magnetic pole around some closed path due to a field H per unit current (in a conductor, say a wire)".

Hence the current definition is redundant, though I suppose it could be mentioned as equivalent using Ampere's law, the definition of work, and the definition of p using H.

Its not sourced anyway (like everything else in the article). I have access to the one piddly book at the bottom, but we need a few more than that. F = q(E+v×B) ⇄ ∑_ic_i 12:34, 7 April 2012 (UTC)

blank and re-direct

This page is to be blanked and re-directed to either magnetic monopoles or magnetic moment, as proposed here. F = q(E+v×B) ⇄ ∑_ic_i 22:02, 7 April 2012 (UTC)