Talk:Metal-mesh optical filter

Untitled

From the article:

The amplitude of both of these electric fields will be equal, and the ratio of their amplitudes is $\Gamma (\omega )$, where $\Gamma$ is the reflection coefficient, and $\omega =g/\lambda$ is the normalized frequency.

But of the aptitude [sic] of both are equal, then the ratio of their amplitudes will be one, so something is unclear here.

This needs review by an expert.

- Leonard G. (talk) 00:25, 4 April 2012 (UTC)