1996 United States House of Representatives elections in Kansas

The 1996 United States House of Representatives elections in Kansas were held on November 5, 1996, to determine who will represent the state of Kansas in the United States House of Representatives. Kansas has four seats in the House, apportioned according to the 1990 United States census. Representatives are elected for two-year terms.

1996 United States House of Representatives elections in Kansas

← 1994 November 5, 1996 1998 →

All 4 Kansas seats to the United States House of Representatives
  Majority party Minority party
 
Party Republican Democratic
Last election 4 0
Seats won 4 0
Seat change Steady Steady
Popular vote 591,146 424,984
Percentage 56.36% 40.52%
Swing Decrease 7.15% Increase 4.03%

Overview

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United States House of Representatives elections in Kansas, 1996[1]
Party Votes Percentage Seats +/–
Republican 591,146 56.36% 4 -
Democratic 424,984 40.52% 0 -
Libertarian 23,253 2.22% 0 -
Reform 9,495 0.91% 0 -
Totals 1,048,878 100.00% 4 -

References

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  1. ^ Clerk of the U.S. House of Representatives. "Statistics of the Presidential and Congressional Election of November 5, 1996" (PDF). U.S. Government Printing Office. p. 25.