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Mr splosh
Joined 9 April 2007
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Team B faced 47.2 overs, so their runrate is
267
47
1
3
=
267
142
3
=
801
142
≈
5.64
{\displaystyle {\frac {267}{47{\tfrac {1}{3}}}}={\frac {267}{\tfrac {142}{3}}}={\frac {801}{142}}\approx 5.64}
Assuming that Team A and Team B had previously played as in the game in scenario one, the new net run rate for team A would be
287
+
265
50
+
50
−
243
+
267
50
+
47
1
3
=
552
100
−
510
97
1
3
≈
0.28
{\displaystyle {\frac {287+265}{50+50}}-{\frac {243+267}{50+47{\tfrac {1}{3}}}}={\frac {552}{100}}-{\frac {510}{97{\tfrac {1}{3}}}}\approx 0.28}
section two
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