Hello, and thank you for wasting your time visiting my user page. My name is Paul and I will leave my last name a really tough mystery for you to solve.
I have been told that I sometimes over-complicate things. I know FOR A FACT that , because the truth is . You can't always believe what people say about you.
One thing I would really appreciate is if a sadistic Calc 202 teacher could have their students evaluate this problem for me in both exact notation and approximation.
When , evaluate
Sadistic calc problem currently under construction.
![{\displaystyle {\vec {r}}(u,v)=\left\langle \left(\pi +{\frac {\cos v}{\sqrt[{\pi }]{2^{e}}}}\right)\cos u,\left(\pi +{\frac {\cos v}{\sqrt[{\pi }]{2^{e}}}}\right)\sin u,{\frac {\sin v}{\sqrt[{\pi }]{2^{e}}}}\right\rangle }](https://wikimedia.org/api/rest_v1/media/math/render/svg/3455da2479e9cc5de0cbe0bf112dd3f0971aae8d)
![{\displaystyle \int _{0}^{5}\int _{5}^{e^{4}+\sin ^{2}(x)}\left.{\frac {\int _{0}^{e^{\pi }}\int _{1024{\sqrt[{e}]{\pi }}}^{2000}\int _{\sin e}^{\int _{\int _{0}^{2\pi }\sin ^{2}x\;dx}^{13}\int _{0}^{\sum _{q=0}^{1000}\sin ^{2}q}\left|{\frac {\partial {\vec {r}}}{\partial v}}\times {\frac {\partial {\vec {r}}}{\partial u}}\right|\;\partial u\;\partial v}\left.{\dfrac {\dfrac {\sqrt[{\sqrt[{a}]{b}}]{c}}{\prod _{k=1}^{\sum _{t=0}^{19}6^{t}}k^{2}}}{\int _{0}^{9}\sin ^{2}\left(e^{f}\right)\;df}}\right.\;\partial c\;\partial b\;\partial a}{x^{\sqrt {g}}}}\right.\;\partial g\;\partial x}](https://wikimedia.org/api/rest_v1/media/math/render/svg/64c52b84b7bacaa7635770400c385f6dbd340b7d)
