Yafujifide

Welcome to my "my talk" page! Yeah!

Search Google for my name to learn all about me.

Simple links

Hello. Please note that there's no need to write [[formal language|formal languages]], since writing [[formal language]]s causes the whole word, not just the part in the brackets, to appear as a clickable link, which links to the article whose name is in the brackets. Similarly [[logic]]al, [[hyphen]]ated, [[Europe]]an, [[Russia]]n, [[apocrypha]]l, [[dogma]]tic, etc. Michael Hardy 00:17, 18 May 2005 (UTC)

Welcome!

Hello, Yafujifide, and welcome to Wikipedia! Thank you for your contributions. I hope you like the place and decide to stay. Here are a few good links for newcomers:

• The five pillars of Wikipedia
• How to edit a page
• Help pages
• Tutorial
• How to write a great article
• Manual of Style

I hope you enjoy editing here and being a Wikipedian! Please sign your name on talk pages using four tildes (~~~~); this will automatically produce your name and the date. If you need help, check out Wikipedia:Where to ask a question, ask me on my talk page, or place {{helpme}} on your talk page and someone will show up shortly to answer your questions. Again, welcome! 

Math notation

Your user page inspires some other comments. You wrote:

$S=\sum _{n=1}^{\infty }{\frac {1}{2^{n}}}={\frac {1}{2}}+{\frac {1}{4}}+{\frac {1}{8}}+{\frac {1}{16}}+...$

You might consider the following form:

$S=\sum _{n=1}^{\infty }{\frac {1}{2^{n}}}={\frac {1}{2}}+{\frac {1}{4}}+{\frac {1}{8}}+{\frac {1}{16}}+\cdots$

or this one:

$S=\sum _{n=1}^{\infty }{\frac {1}{2^{n}}}={\frac {1}{2}}+{\frac {1}{4}}+{\frac {1}{8}}+{\frac {1}{16}}+\dots$

In one of these, the three dots ... are centered -- aligned with the preceeding "+" sign. In both of these, the dots are farther apart than in your version. As you'll see if you click on "edit this page", one of these uses \cdots and the other uses \dots. I prefer \cdots in this situation. Also, on Wikipedia, it is conventional to indent "displayed" TeX by means of an invisible colon, thus:

$S=\sum _{n=1}^{\infty }{\frac {1}{2^{n}}}={\frac {1}{2}}+{\frac {1}{4}}+{\frac {1}{8}}+{\frac {1}{16}}+\cdots$

Michael Hardy 00:22, 18 May 2005 (UTC)